Answer
$1 $ $and $ $\frac{1}{2}$
Work Step by Step
$x^{2}-(2-3x)^{2}=0$
$x^{2}=(2-3x)^{2}$
$2-3x=\pm\sqrt x^{2}$
$2-3x=\pm x$
$When 2-3x=x$
$2=4x$
$x=\frac{1}{2}$
$When 2-3x=-x$
$2=2x$
$x=1$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 17: 112
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