Answer
$\frac{\sqrt[3] y^{2}}{\sqrt[3] x^{2}}$
Work Step by Step
$(\frac{x}{y})^{-\frac{1}{3}}(\frac{y}{x})^{\frac{1}{3}}=\frac{x^{-\frac{1}{3}}y^{\frac{1}{3}}}{y^{-\frac{1}{3}}x^{\frac{1}{3}}}=x^{-\frac{1}{3}-\frac{1}{3}}y^{\frac{1}{3}-(-\frac{1}{3})}=x^{-\frac{2}{3}}y^{\frac{2}{3}}=\frac{y^{\frac{2}{3}}}{x^{\frac{2}{3}}}=\frac{\sqrt[3] y^{2}}{\sqrt[3] x^{2}}$
