Answer
$-1 and -\frac{1}{3}$
Work Step by Step
$x^{2}-(1+2x)^{2}=0$
$x^{2}=(1+2x)^{2}$
$1+2x=\pm\sqrt x^{2}$
$1+2x=\pm x$
$When 1+2x=x$
$1+x=0$
$x=-1$
$When 1+2x=-x$
$1+3x=0$
$3x=-1$
$x=-\frac{1}{3}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 17: 111
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