Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 17: 98

Answer

$$\frac{1}{{\root a \of 2 }}$$

Work Step by Step

$$\eqalign{ & \frac{{{2^{1/a}}}}{{{2^{2/a}}}} \cr & {\text{Use the exponent identity }}\frac{{{a^m}}}{{{a^n}}} = {a^{m - n}} \cr & \frac{{{2^{1/a}}}}{{{2^{2/a}}}} = {2^{1/a - 2/a}} \cr & \frac{{{2^{1/a}}}}{{{2^{2/a}}}} = {2^{\frac{{1 - 2}}{a}}} \cr & {\text{Simplifying}} \cr & \frac{{{2^{1/a}}}}{{{2^{2/a}}}} = {2^{ - \frac{1}{a}}} \cr & {\text{Use negative integer exponent rule }}{a^{ - n}} = \frac{1}{{{a^n}}} \cr & = \frac{1}{{{2^{1/a}}}} \cr & {\text{Using radical properties}} \cr & = \frac{1}{{\root a \of 2 }} \cr} $$
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