Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.2 - Exponents and Radicals - Exercises - Page 17: 103

Answer

$\frac{x^{\frac{1}{2}}y^2}{x^{-\frac{1}{2}}y} =xy$

Work Step by Step

By the formula on page 9, $\frac{x^{\frac{1}{2}}y^2}{x^{-\frac{1}{2}}y} = x^{\frac{1}{2}- (-\frac{1}{2})}y^{2-1} = x^{1}y^{1} = xy$.
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