Answer
$= \log 2 + 2 \log x - \log y$
Work Step by Step
$ \log (\frac{2x^{2}}{y})$
$= \log 2x^{2} - \log y$
$= \log 2 + \log x^{2} - \log y$
$= \log 2 + 2 \log x - \log y$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - 6.4 Properties of Logarithms - 6.4 Exercises - Page 516: 15
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