Answer
$= \ln \frac{\sqrt {7ab^{3}}}{c^{4}}$
Work Step by Step
$= \frac{1}{2} \ln 7 + \frac{1}{2} \ln a + \frac{3}{2} \ln b - 4 \ln c$
$= \ln \sqrt 7 + \ln \sqrt a + \ln \sqrt {b^{3}} - \ln c^{4}$
$= \ln \sqrt {7ab^{3}}- \ln c^{4}$
$= \ln \frac{\sqrt {7ab^{3}}}{c^{4}}$
