Answer
$= \log \frac{3x^{3}y^{4}}{7}$
Work Step by Step
$= \log 3 + 3 \log x + 4 \log y - \log 7$
$= \log 3 + \log x^{3} + \log y^{4} - \log 7$
$= \log 3x^{3} + \log y^{4} - \log 7$
$= \log 3x^{3}y^{4}- \log 7$
$= \log \frac{3x^{3}y^{4}}{7}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - 6.4 Properties of Logarithms - 6.4 Exercises - Page 516: 36
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