Answer
$= \frac{1}{2} \ln 6 + \frac{1}{2} \ln a$
Work Step by Step
$= \ln (\sqrt {6a})$
$= \ln (6a)^{\frac{1}{2}}$
$= \frac{1}{2} \ln 6a$
$= \frac{1}{2} \ln 6 + \frac{1}{2} \ln a$
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