Answer
$= \log \frac{3x^{4}}{49y^{2}}$
Work Step by Step
$= \log 3x + 3 \log x - 2\log 7y$
$= \log 3x + \log x^{3} - \log (7y)^{2}$
$= \log 3x^{4}- \log (7y)^{2}$
$= \log 3x^{4}- \log 49y^{2}$
$= \log \frac{3x^{4}}{49y^{2}}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - 6.4 Properties of Logarithms - 6.4 Exercises - Page 516: 44
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