Answer
$= \frac{1}{2} \ln 7 + \frac{1}{2} \ln a + \frac{1}{2} \ln b$
Work Step by Step
$= \ln (\sqrt {7ab})$
$= \ln (7ab)^{\frac{1}{2}}$
$= \frac{1}{2}\ln (7ab)$
$= \frac{1}{2} \ln 7 + \frac{1}{2} \ln a + \frac{1}{2} \ln b$
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