Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 50

Answer

$36y^{2}-9$

Work Step by Step

From Page 301, we know that the product of a sum and difference of two terms $x$ and $y$ is given by the following equation: $(x+y)(x-y)=x^{2}-y^{2}$. Therefore, $(6y-3)(6y+3)=(6y)^{2}-3^{2}=6^{2}y^{2}-9=36y^{2}-9$.
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