Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises - Page 304: 33

Answer

$m^{2}-3m-40$

Work Step by Step

We are given the expression $(m+5)(m-8)$. We can find the product of this expression using the FOIL method. First terms: $m\times m=m^{2}$ Outer terms: $m\times-8=-8m$ Inner terms: $5\times m=5m$ Last terms: $5\times-8=-40$ Adding together: $m^{2}+(-8m)+5m+(-40)=m^{2}-8m+5m-40=m^{2}-3m-40$
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