Answer
$m^{2}-3m-40$
Work Step by Step
We are given the expression $(m+5)(m-8)$. We can find the product of this expression using the FOIL method.
First terms: $m\times m=m^{2}$
Outer terms: $m\times-8=-8m$
Inner terms: $5\times m=5m$
Last terms: $5\times-8=-40$
Adding together: $m^{2}+(-8m)+5m+(-40)=m^{2}-8m+5m-40=m^{2}-3m-40$