Intermediate Algebra (12th Edition)

$6y^2+y-12$
Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL Method, the product of the binomials in the given expression, $(2y+3)(3y-4) ,$ is \begin{array}{l}\require{cancel} 2y(3y)+2y(-4)+3(3y)+3(-4) \\\\= 6y^2-8y+9y-12 \\\\= 6y^2+y-12 .\end{array}