Answer
$12k^{2}+k-6$
Work Step by Step
We are given the expression $(4k+3)(3k-2)$. We can find the product of this expression using the FOIL method.
First terms: $4k\times 3k=12k^{2}$
Outer terms: $4k\times-2=-8k$
Inner terms: $3\times 3k=9k$
Last terms: $3\times-2=-6$
Adding together: $12k^{2}+(-8k)+9k+(-6)=12k^{2}-8k+9k-6=12k^{2}+k-6$
