Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 2

Answer

A. $6x^{2}+23x+20$

Work Step by Step

We are given the expression $(2x+5)(3x+4)$. We can find the product of this expression using the FOIL method. First terms: $2x\times 3x=6x^{2}$ Outer terms: $2x\times4=8x$ Inner terms: $5\times 3x=15x$ Last terms: $5\times4=20$ Adding together: $6x^{2}+8x+15x+20=6x^{2}+8x+15x+20=6x^{2}+23x+20$
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