Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 20

Answer

$32y^3+4y^2-6y$

Work Step by Step

Using the Distributive Property, the product of the given expression, $ 2y(2y+1)(8y-3) ,$ is \begin{array}{l}\require{cancel} [2y(2y)+2y(1)](8y-3) \\\\= [4y^2+2y](8y-3) \\\\= 4y^2(8y)+4y^2(-3)+2y(8y)+2y(-3) \\\\= 32y^3-12y^2+16y^2-6y \\\\= 32y^3+4y^2-6y .\end{array}
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