Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 40

Answer

$6x^{2}+17xy+12y^{2}$

Work Step by Step

We are given the expression $(3x+4y)(2x+3y)$. We can find the product of this expression using the FOIL method. First terms: $3x\times 2x=6x^{2}$ Outer terms: $3x\times3y=9xy$ Inner terms: $4y\times 2x=8xy$ Last terms: $4y\times3y=12y^{2}$ Adding together: $6x^{2}+9xy+8xy+12y^{2}=6x^{2}+17xy+12y^{2}$
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