Answer
D. $6x^{2}-23x+20$
Work Step by Step
We are given the expression $(2x-5)(3x-4)$. We can find the product of this expression using the FOIL method.
First terms: $2x\times 3x=6x^{2}$
Outer terms: $2x\times-4=-8x$
Inner terms: $-5\times 3x=-15x$
Last terms: $-5\times-4=20$
Adding together: $6x^{2}+(-8x)+(-15x)+20=6x^{2}-8x-15x+20=6x^{2}-23x+20$