Answer
$6t^3+t^2-14t-3$
Work Step by Step
Using the Distributive Property, the product of the given expression, $
(2t+3)(3t^2-4t-1)
,$ is
\begin{array}{l}\require{cancel}
2t(3t^2)+2t(-4t)+2t(-1)+3(3t^2)+3(-4t)+3(-1)
\\\\=
6t^3-8t^2-2t+9t^2-12t-3
\\\\=
6t^3+(-8t^2+9t^2)+(-2t-12t)-3
\\\\=
6t^3+t^2-14t-3
.\end{array}