Answer
$10w^{2}-21w-10$
Work Step by Step
We are given the expression $(5w+2)(2w-5)$. We can find the product of this expression using the FOIL method.
First terms: $5w\times 2w=10w^{2}$
Outer terms: $5w\times-5=-25w$
Inner terms: $2\times 2w=4w$
Last terms: $2\times-5=-10$
Adding together: $10w^{2}+(-25w)+4w+(-10)=10w^{2}-25w+4w-10=10w^{2}-21w-10$