Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 36

Answer

$10w^{2}-21w-10$

Work Step by Step

We are given the expression $(5w+2)(2w-5)$. We can find the product of this expression using the FOIL method. First terms: $5w\times 2w=10w^{2}$ Outer terms: $5w\times-5=-25w$ Inner terms: $2\times 2w=4w$ Last terms: $2\times-5=-10$ Adding together: $10w^{2}+(-25w)+4w+(-10)=10w^{2}-25w+4w-10=10w^{2}-21w-10$
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