Answer
$\left(\begin{array}{l} 10\\ 5 \end{array}\right)=252$
Work Step by Step
We evaluate:
$\left(\begin{array}{l} 10\\ 5 \end{array}\right)=\frac{10!}{5!5!}=\frac{10*9*8*7*6*5!}{5!*5*4*3*2*1}=\frac{10*9*8*7*6}{5*4*3*2}=\frac{30240}{120}=252$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises - Page 636: 20
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