College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises: 12

Answer

$99+70\sqrt{2}$

Work Step by Step

We use the values from the 6th row of Pascal's Triangle to find the coefficients: $(1+\sqrt{2})^{6}=1^{6}+6*1^{5}*\sqrt{2}+15*1^{4}*2+20*1^{3}*2\sqrt{2}+15* 1^{2}* 4+6* 1^1* 4\sqrt{2}+2^{3}1^0=1+6\sqrt{2}+30+40\sqrt{2}+60+24\sqrt{2}+8=99+70\sqrt{2}$
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