College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises: 14

Answer

$(1+x^{3})^{3}=1+3x^{3}+3x^{6}+x^{9}$

Work Step by Step

We use the values from the 3rd row of Pascal's Triangle to find the coefficients: $(1+x^{3})^{3}=1^{3}+3* 1^{2}*(x^{3})^1+3* 1(x^{3})^{2}+(x^{3})^{3}=1+3x^{3}+3x^{6}+x^{9}$
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