Answer
$(x+ \frac{1}{x})^{4}=x^{4}+4x^{2}+6+\frac{4}{x^{2}}+\frac{1}{x^{4}}$
Work Step by Step
We use the values from the 4th row of Pascal's Triangle to find the coefficients:
$(x+ \frac{1}{x})^{4}=x^{4}+4x^{3}(\frac{1}{x})^1+6x^{2}(\frac{1}{x})^{2}+4x(\frac{1}{x})^{3}+(\frac{1}{x})^{4}=x^{4}+4x^{2}+6+\frac{4}{x^{2}}+\frac{1}{x^{4}}$
