Answer
$100y^{99}$
Work Step by Step
We find the 100th term in the expansion of $(1+y)^{100}$ by using Binomial Theorem coefficients:
$\left(\begin{array}{l}
100\\99\end{array}\right)1^{1}y^{99}=100(1^1)(y^{99})=100y^{99}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises - Page 636: 37
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