College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises: 44

Answer

$[(x-1)+1]^{5}=x^{5}$

Work Step by Step

We need to factor: $(x-1)^{5}+5(x-1)^{4}+10(x-1)^{3}+10(x-1)^{2}+5(x-1)+1$ We notice that this corresponds to an expanded binomial with a power of $5$ and terms $x-1$ and $1$: $[(x-1)+1]^{5}=x^{5}$
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