College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises - Page 636: 18

Answer

$\left(\begin{array}{l} 8\\ 3 \end{array}\right)=56$

Work Step by Step

We evaluate: $\left(\begin{array}{l} 8\\ 3 \end{array}\right)=\frac{8!}{3!5!}=\frac{8*7*6*5!}{3*2*1*5!}=\frac{8*7*6}{3*2}=8*7=56$
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