Answer
$(x-1)^{5}=x^{5}-5x^{4}+10x^{3}-10x^{2}+5x-1$
Work Step by Step
We use the values from the 5th row of Pascal's Triangle to find the coefficients:
$(x-1)^{5}=x^{5}+-5x^{4}+10x^{3}+-10x^{2}+5x^1-1=
x^{5}-5x^{4}+10x^{3}-10x^{2}+5x-1$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises - Page 636: 9
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