Answer
We expand using the Binomial Theorem:
$(1-x)^{5}=1-5x+10x^{2}-10x^{3}+5x^{4}-x^{5}$
Work Step by Step
We expand using the Binomial Theorem:
$(1-x)^{5}=\left(\begin{array}{l} 5\\ 0 \end{array}\right)(1)^{5}-\left(\begin{array}{l} 5\\ 1 \end{array}\right) (1)^{4}x^{1}+\left(\begin{array}{l} 5\\ 2 \end{array}\right)(1)^{3}x^{2}-\left(\begin{array}{l} 5\\ 3 \end{array}\right)(1)^{2}x^{3}+\left(\begin{array}{l} 5\\ 4 \end{array}\right)(1)^{1}x^{4}-\left(\begin{array}{l} 5\\ 5 \end{array}\right)x^{5}=1-5x+10x^{2}-10x^{3}+5x^{4}-x^{5}$
