Answer
$-4060A^{3}B^{27}$
Work Step by Step
We find the 28th term in the expansion of $(A-B)^{30}$ by using Binomial Theorem coefficients:
$\left(\begin{array}{l}
30\\27\end{array}\right)A^{3}(-B)^{27}=4060(A^{3})(-B^{27})=-4060A^{3}B^{27}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 8, Sequences and Series - Section 8.6 - The Binomial Theorem - 8.6 Exercises - Page 636: 36
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