College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Chapter 8 Review - Exercises - Page 640: 24

Answer

$a_n=2(1+i)^{n-1}$

Work Step by Step

We are given the geometric sequence $\{a_n\}$: $$2,2+2i,4i,-4+4i,-8,\dots$$ Determine the common ratio $r$: $$r=\dfrac{a_2}{a_1}=\dfrac{2+2i}{2}=1+i.$$ The elements of the geometric sequence are: $$\begin{cases} a_1=2\\ r=1+i. \end{cases}$$ Calculate the $n$th term: $$a_n=a_1r^{n-1}=2(1+i)^{n-1}.$$
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