Answer
$0^2+1^2+2^2+3^2+4^2+5^2+6^2+7^2+8^2+9^2$
Work Step by Step
We rewrite the given sum by expanding it: in each term $(k-1)^2$ substitute the values of $k$, where $k=1,2,\dots,10$:
$$\begin{align*}
\sum_{k=1}^{10} (k-1)^2&=(1-1)^2+(2-1)^2+(3-1)^2+(4-1)^2+(5-1)^2+(6-1)^2+(7-1)^2+(8-1)^2+(9-1)^2+(10-1)^2\\
&=0^2+1^2+2^2+3^2+4^2+5^2+6^2+7^2+8^2+9^2.
\end{align*}$$
