Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 210: 4-158

Answer

1. C 2. B 3. D 4. D 5. A

Work Step by Step

1. $c_p=c_v+R\rightarrow (0.7+0.3)kJ/kg.K=1.0 kJ/kg.K$ $\Delta h=c_p\Delta T=1.0\ kJ/kg.K\times100K=100kJ/kg$ 2. $\Delta u=c_v\Delta T=0.7\ kJ/kg.K\times100K=70kJ/kg$ 3,4. Not enough information about the process. 5. $\Delta h = \Delta u + \Delta (Pv)$ $\Delta (Pv)=30\ kJ/kg$
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