Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 210: 4-151

Answer

C

Work Step by Step

$Q=mc_v\Delta T$ $m=6\times0.355\ kg=2.13\ kg$ $c_v=4.18\ kJ/kg.K,\ \Delta T=(3-18)°C=-15°C$ $Q=-133.55\ kJ$
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