Answer
B
Work Step by Step
$Q_{max}=\Delta U_{max} \rightarrow T_2=95°C$
$Q_{max}=mc_v\Delta T_{max}$
$Q_{max}=0.1kg\times3.32kJ/kg.K\times(95-5)K=29.88kJ$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 210: 4-155
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