Answer
B
Work Step by Step
Isothermal boundary work:
$W_b=P_1V_1\ln(\frac{V_2}{V_1})$
Given $P_1=600\ kPa,\ V_1=0.5\ m³,\ V_2=0.1\ m³$
$W_b=-482.8\ kJ$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 210: 4-146
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