Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 210: 4-147

Answer

E

Work Step by Step

Energy balance: $Q-W_s=\Delta U$ With $Q=0.8\ kJ/s\times 30\ min\times 60\ s/min=1440\ kJ$ $W_e=-120 J/s\times 30\ min\times 60\ s/min=-216\ kJ$ $\Delta U=1656\ kJ=mc_v\Delta T$ Given $m=60kg,\ c_v=0.718\ kJ/kg.K,\ T_1=25°C$ $T_2=63.4°C$
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