Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 210: 4-157

Answer

C

Work Step by Step

$\Delta u=\int c_vdT=(0.7\ T+1.35\times10^{-4}T^2)|_{T_1}^{T_2}$ With $T_2=400K, T_1=300K$: $\Delta u=79.45\ kJ/kg$
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