Answer
$V_{tank}=2.796m^3$
Work Step by Step
From table A-12:
$\upsilon_{1}=0.000858\frac{m^3}{kg}$
$m=\frac{V_{1}}{\upsilon_{1}}=\frac{0.03m^3}{0.000858\frac{m^3}{kg}}=34.965kg$
From table A-13:
$\upsilon_{2}=0.07997\frac{m^3}{kg}$
$V_{tank}=m\upsilon_{2}=34.965kg*0.07997\frac{m^3}{kg}=2.796m^3$
