Answer
$Percent=6.9\%$
Work Step by Step
$P_{1}=200kPa+90kPa=290kPa$
$P_{2}=220kPa+90kPa=310kPa$
As $V_{1}=V_{2}$
$m_{1}=m_{2}$
$\frac{P_{1}V_{1}}{RT_{1}}=\frac{P_{2}V_{2}}{RT_{2}}$
Simplifying and solving for $T_{2}$:
$\frac{T_{2}}{T_{1}}=\frac{P_{2}}{P_{1}}=\frac{310kPa}{290kPa}=1.069$
The percent increase in the absolute temperature of the air in the tire is:
$Percent=0.069*100=6.9\%$
