Answer
With $V=4L$: Liquid
With $V=400L$: Vapor
Work Step by Step
With $V=4L$
$\upsilon_{1}=\frac{4L*\frac{1m^3}{1000L}}{2kg}=0.002\frac{m^3}{kg}$
As $\upsilon_{1}\lt \upsilon_{cr}$ is a liquid.
With $V=400L$
$\upsilon_{2}=\frac{400L*\frac{1m^3}{1000L}}{2kg}=0.2\frac{m^3}{kg}$
As $\upsilon_{2}\gt \upsilon_{cr}$ is a vapor.
