Answer
a)$P=15532.94kPa$
b) $P=12574.2kPa$
c)$P=12517.21kPa$
Work Step by Step
a) Based on the ideal gas equation:
$P=\frac{RT}{\upsilon}=\frac{0.4615\frac{kPam^3}{kgK}*(400+273.15)K}{0.02\frac{m^3}{kg}}=15532.94kPa$
b) Using the generalized compressibility chart:
$T_{R}=\frac{T}{T_{cr}}=\frac{673.15K}{647.1K}=1.040$
$\upsilon_{R}=\frac{\upsilon}{\frac{RT_{cr}}{P_{cr}}}=\frac{0.02\frac{m^3}{kg}}{\frac{0.4615\frac{kPam^3}{kgK}*647.1K}{22060kPa}}=1.48$
From Fig A-15
$P_{R}=0.57$
Then
$P=P_{R}*P_{cr}=0.57*22060=12574.2kPa$
c)Interpolating from table A-6:
$P=12517.21kPa$
