Answer
a) $T_{2}=1246K$
b)$T_{2}=826K$
c) $T_{2}=750K$
Work Step by Step
Knowing that:
$P_{1}=P_{2}$
$m_{1}=m_{2}$
$V_{2}=2V_{1}$
a) From the ideal gas law:
$\frac{m_{1}RT_{1}}{V_{1}}=\frac{m_{2}RT_{2}}{V_{2}}$
Substituting and simplifying:
$T_{2}=2T_{1}=2(350+273)=1246K$
b) Using the generalized compressibility chart:
From table A-4:
$P_{1}=16529kPa$
$P_{R,1}=\frac{P_{1}}{P_{cr}}=\frac{16.529MPa}{22.06MPa}=0.749$
$T_{R,1}=\frac{T_{1}}{T_{cr}}=\frac{623K}{647.1K}=0.963$
From Fig A-15
$Z=0.593$
$\upsilon_{R,1}=0.75$
$\upsilon_{R,2}=2*0.75=1.5$
$P_{R,2}=0.749$
From Fig A-15
$Z=0.88$
Then:
$T_{2}=\frac{P_{2}\upsilon_{2}}{Z_{2}R}=\frac{P_{2}\upsilon_{R,2}T_{cr}}{Z_{2}P_{cr}}=\frac{16529kPa*1.5*647.1K}{0.88*22060kPa}=826K$
c) From table A-4:
$\upsilon_{1}=0.008806\frac{m^3}{kg}$
$\upsilon_{2}=2\upsilon_{1}=0.01761\frac{m^3}{kg}$
From table A-6:
$T_{2}=477^{\circ}C=750K$
