Answer
$P_{2}=275kPa$
Work Step by Step
Knowing that:
$T_{1}=T_{2}$
$m_{1}=m_{2}$
$V_{2}=2V_{1}$
From ideal gas law:
$T=\frac{PV}{mT}$
Then:
$\frac{P_{1}V_{1}}{m_{1}T_{1}}=\frac{P_{2}V_{2}}{m_{2}T_{2}}$
Substituting and simplifying:
$P_{1}V_{1}=P_{2}*2V_{1}$
Solving for P_{2}:
$P_{2}=\frac{P_{1}}{2}=\frac{550kPa}{2}=275kPa$
