Answer
$T_{2}=3327.3^{\circ}C$
Work Step by Step
Knowing that:
$P_{1}=P_{2}$
$V_{2}=3V_{1}$
$m_{1}=m_{2}$
From the ideal gas law:
$P=\frac{mRT}{V}$
Then:
$\frac{m_{1}RT_{1}}{V_{1}}=\frac{m_{2}RT_{2}}{V_{2}}$
Simplifying and substituting:
$\frac{T_{1}}{V_{1}}=\frac{T_{2}}{3V_{1}}$
Solving for $T_{2}$
$T_{2}=3T_{1}=3*(927+273.15)K=3600.45K$
$T_{2}=3327.3^{\circ}C$
