Answer
a) $m=49.603kg$
b) $T_{2}=120.21^{\circ}C$
c)$\Delta H=125930.61kJ$
d) Show in the image
Work Step by Step
1) Here we are working with compress liquid, from table A-4:
$\upsilon_{1}=0.001008\frac{m^3}{kg}$
$V_{1}=50L*\frac{1m^3}{1000L}=0.05m^3$
a) $m=\frac{V_{1}}{\upsilon_{1}}=\frac{0.05m^3}{0.001008\frac{m^3}{kg}}=49.603kg$
$h_{1}=167.53\frac{kJ}{kg}$
2) Now with a saturated mix:
b) From table A-5:
$T_{2}=120.21^{\circ}C$
$h_{2}=2706.3\frac{kJ}{kg}$
c)$\Delta H=m\Delta h=49.603kg*(2706.3\frac{kJ}{kg}-167.53\frac{kJ}{kg})=125930.61kJ$
