Answer
$m=19.08kg$
Work Step by Step
$P_{abs}=97kPa+500kPa=597kPa$
From the ideal gas law:
$m=\frac{PV}{RT}=\frac{597kPa*2.5m^3}{0.2598\frac{kPam^3}{kgK}*(28+273.15)K}=19.08kg$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 3 - Properties of Pure Substances - Problems - Page 156: 3-71
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