Answer
$P_{gage}=972.61kPa$
Work Step by Step
From the ideal gas law:
$P=\frac{mRT}{V}$
$P=\frac{5kg*0.287\frac{kPam^3}{kgK}*(25+273.15)K}{400L*\frac{1m^3}{100L}}=1069.61kPa$
$P_{gage}=1069.61kPa-97kPa=972.61kPa$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 3 - Properties of Pure Substances - Problems - Page 156: 3-68
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