Answer
$V=4.16m^3$
Work Step by Step
From the ideal gas law:
$V=\frac{mRT}{P}$
$V=\frac{2kg*2.0769\frac{kPam^3}{kgK}*(27+273.15)K}{300kPa}=4.16m^3$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 3 - Properties of Pure Substances - Problems - Page 156: 3-70
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